Integrand size = 11, antiderivative size = 47 \[ \int \frac {x^2}{(a+b x)^{10}} \, dx=-\frac {a^2}{9 b^3 (a+b x)^9}+\frac {a}{4 b^3 (a+b x)^8}-\frac {1}{7 b^3 (a+b x)^7} \]
[Out]
Time = 0.01 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {45} \[ \int \frac {x^2}{(a+b x)^{10}} \, dx=-\frac {a^2}{9 b^3 (a+b x)^9}+\frac {a}{4 b^3 (a+b x)^8}-\frac {1}{7 b^3 (a+b x)^7} \]
[In]
[Out]
Rule 45
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {a^2}{b^2 (a+b x)^{10}}-\frac {2 a}{b^2 (a+b x)^9}+\frac {1}{b^2 (a+b x)^8}\right ) \, dx \\ & = -\frac {a^2}{9 b^3 (a+b x)^9}+\frac {a}{4 b^3 (a+b x)^8}-\frac {1}{7 b^3 (a+b x)^7} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.66 \[ \int \frac {x^2}{(a+b x)^{10}} \, dx=-\frac {a^2+9 a b x+36 b^2 x^2}{252 b^3 (a+b x)^9} \]
[In]
[Out]
Time = 0.04 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.64
method | result | size |
gosper | \(-\frac {36 b^{2} x^{2}+9 a b x +a^{2}}{252 \left (b x +a \right )^{9} b^{3}}\) | \(30\) |
norman | \(\frac {-\frac {x^{2}}{7 b}-\frac {a x}{28 b^{2}}-\frac {a^{2}}{252 b^{3}}}{\left (b x +a \right )^{9}}\) | \(33\) |
risch | \(\frac {-\frac {x^{2}}{7 b}-\frac {a x}{28 b^{2}}-\frac {a^{2}}{252 b^{3}}}{\left (b x +a \right )^{9}}\) | \(33\) |
parallelrisch | \(\frac {-36 b^{8} x^{2}-9 a \,b^{7} x -a^{2} b^{6}}{252 b^{9} \left (b x +a \right )^{9}}\) | \(37\) |
default | \(-\frac {a^{2}}{9 b^{3} \left (b x +a \right )^{9}}+\frac {a}{4 b^{3} \left (b x +a \right )^{8}}-\frac {1}{7 b^{3} \left (b x +a \right )^{7}}\) | \(42\) |
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 120 vs. \(2 (41) = 82\).
Time = 0.22 (sec) , antiderivative size = 120, normalized size of antiderivative = 2.55 \[ \int \frac {x^2}{(a+b x)^{10}} \, dx=-\frac {36 \, b^{2} x^{2} + 9 \, a b x + a^{2}}{252 \, {\left (b^{12} x^{9} + 9 \, a b^{11} x^{8} + 36 \, a^{2} b^{10} x^{7} + 84 \, a^{3} b^{9} x^{6} + 126 \, a^{4} b^{8} x^{5} + 126 \, a^{5} b^{7} x^{4} + 84 \, a^{6} b^{6} x^{3} + 36 \, a^{7} b^{5} x^{2} + 9 \, a^{8} b^{4} x + a^{9} b^{3}\right )}} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 128 vs. \(2 (41) = 82\).
Time = 0.44 (sec) , antiderivative size = 128, normalized size of antiderivative = 2.72 \[ \int \frac {x^2}{(a+b x)^{10}} \, dx=\frac {- a^{2} - 9 a b x - 36 b^{2} x^{2}}{252 a^{9} b^{3} + 2268 a^{8} b^{4} x + 9072 a^{7} b^{5} x^{2} + 21168 a^{6} b^{6} x^{3} + 31752 a^{5} b^{7} x^{4} + 31752 a^{4} b^{8} x^{5} + 21168 a^{3} b^{9} x^{6} + 9072 a^{2} b^{10} x^{7} + 2268 a b^{11} x^{8} + 252 b^{12} x^{9}} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 120 vs. \(2 (41) = 82\).
Time = 0.20 (sec) , antiderivative size = 120, normalized size of antiderivative = 2.55 \[ \int \frac {x^2}{(a+b x)^{10}} \, dx=-\frac {36 \, b^{2} x^{2} + 9 \, a b x + a^{2}}{252 \, {\left (b^{12} x^{9} + 9 \, a b^{11} x^{8} + 36 \, a^{2} b^{10} x^{7} + 84 \, a^{3} b^{9} x^{6} + 126 \, a^{4} b^{8} x^{5} + 126 \, a^{5} b^{7} x^{4} + 84 \, a^{6} b^{6} x^{3} + 36 \, a^{7} b^{5} x^{2} + 9 \, a^{8} b^{4} x + a^{9} b^{3}\right )}} \]
[In]
[Out]
none
Time = 0.29 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.62 \[ \int \frac {x^2}{(a+b x)^{10}} \, dx=-\frac {36 \, b^{2} x^{2} + 9 \, a b x + a^{2}}{252 \, {\left (b x + a\right )}^{9} b^{3}} \]
[In]
[Out]
Time = 0.15 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.66 \[ \int \frac {x^2}{(a+b x)^{10}} \, dx=-\frac {8\,a^2+72\,a\,b\,x+288\,b^2\,x^2}{2016\,b^3\,{\left (a+b\,x\right )}^9} \]
[In]
[Out]